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5x^2-2x=3x-5x-5x^2
We move all terms to the left:
5x^2-2x-(3x-5x-5x^2)=0
We get rid of parentheses
5x^2+5x^2-3x+5x-2x=0
We add all the numbers together, and all the variables
10x^2=0
a = 10; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·10·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation
Stosujemy wzór:$x=\frac{-b}{2a}=\frac{0}{20}=0$
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